4-8x/x^2-x

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Solution for 4-8x/x^2-x equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

4-x-((8*x)/(x^2)) = 0

4-x-8*x^-1 = 0

4*x^0-1*x^1-8*x^-1 = 0

(4*x^1-1*x^2-8*x^0)/(x^1) = 0 // * x^2

x^1*(4*x^1-1*x^2-8*x^0) = 0

x^1

4*x-x^2-8 = 0

4*x-x^2-8 = 0

DELTA = 4^2-(-8*(-1)*4)

DELTA = -16

DELTA < 0

x in { } 

x belongs to the empty set

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